Matric and various vector math hints and tips.
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General Matrix calculation is by
[x,y,z] * M => [x',y',z']
|x| |x'|
or M * |y| => |y'|
|z| |z'|
The result is the same in either case. As long as the matrix was created using
row vectors OR column vectors to match!
Which style is used is up to the matrix library version you use. I prefer
the former, which The perl Math::MatrixReal library seems to like the later.
Just note the order.
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Matrix and what the terms actually mean...
From the povray matrix page..
http://enphilistor.users4.50megs.com/matrix.htm
Generally a matrix is defined (at least in Povray) as...
| A.x A.y A.z 0 |
| B.x B.y B.z 0 |
| C.x C.y C.z 0 |
| D.x D.y D.z 1 |
This can be thought of a a matrix of four (row) vectors A, B, C, D
where A = | A.x, A.y, A.z, 0 | etc. (NB: A.x is the x component of A)
What this matrix does is wrap the 3D space so that the X axis moves (rotates,
scales, shear, etc) to vector A, ditto for Y -> B and Z -> C. The last vector
D is the new location for the Origin (translate).
As the page above specifies this means that if you create a set of orthogonal
vectors A,B,C general rotations are very easy to do, and goes on to provide a
two part solution to rotating any general vector to any other general vector
(while retaining an general up direction).
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Orthogonal Matrices
A matrix is orthogonal if each of the three vectors making up the matrix
are orthogonal. That is they are all perpenducular to each other.
This is true of all rotation matrices (no scaling or shear).
What is interesting is that the inverse of such matrices is also its
transpose. And that matrix in itself is also orthogonal.
This means if we have a rotation matix
| A.x A.y A.z |
| B.x B.y B.z |
| C.x C.y C.z |
To rotate the x,y,z axises to the A,B,C vectors, then it so happens that
the inverse (rotate A,B,C vectors to the x,y,z axises) is the matrixes
transpose (diagonal mirror).
| A.x B.x C.x |
| A.y B.y C.y |
| A.z B.z C.z |
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Rotation Matrices are...
Normilized or Each row or column are unit vectors (vector length = 1)
Orthogonal or Dot product of any row to to any other row
or column to column is 0
EG: All row or column vectors are perpendicular to each other
Its Inverse is also its Transpose (due to orthogonality)
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Rotation Matrix about axis (x,y,z) and angle a
Given that s = sin(a) c = cos(a) t = (1 - cos(a))
and x, y, z defines the axis you want to rotate around
then, the rotation matrix is...
| txx+c txy+sz txz-sy |
R = | txy-sz tyy+c tyz+sx |
| txz+sy tyz-sx tzz+c |
For very small angles (and you later occasionally re-normalize)
A technique often used for interactive rotations using a mouse.
Then s = sin(a) => a c = cos(a) => 1 t => 0
and thus rotation becomes
| 1 za -ya |
R = | -za 1 xa |
| ya -xa 1 |
Given a orthogonal rotation matrix
Then the axis and angle of rotation can be found using...
cos(a) = ( R[0][0] + R[1][1] + R[2][2] - 1 ) / 2
axis = ( R[1][2]-R[2][1], R[2][0]-R[0][2], R[0][1]-R[1][0] ) / 2*sin(a)
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General Rotatation of a unit vector V to unit vector W
(rotation in same plain as both vectors - ie: the minimal rotation)
This is complex and difficult if you try to generate it using the
above general axis and angle method. The following generates it faster
and more simply, without need for sin() and cosin() functions, using the
meaning of the three vectors in a roatation matrix.
To do this requires three steps...
1/ Matrix to rotate the Vector V onto some arbatary axis (eg: X)
but such that the vector W also rotates to W' in the XY plan!
2/ One to rotate about the Z axis so that the rotated vector V'
(which is now at the X axis) is rotated to W' in that frame work.
3/ Rotate back to the original axis frame work by using the
inverse (transpose) of the original rotation.
First Step
It is easier to calculate the last step and invert the matrix, so...
We need to find two more unit vectors orthogonal to the original
vector V. One of these vectors must be the axis of rotation
so it can be moved to the Z axis for the second step.
Find the axis of rotation N
N = normalised ( V x W )
And the other orthogonal axis to complete the axis frame work.
M = N x V (note M is unit length as N and V are orthoginal)
alturnativally...
M = normailzed( V x W x V )
to rotate the X Y Z axis to this frame work would thus be...
| Vx, Vy, Vz |
Q = | Mx, My, Mz | (NB: a matrix of row vectors)
| Nx, Ny, Nz |
But for this step we want to do the oppisite! So inverse the orthogonal
matrix by transposing (diagonal flip). So the first step is....
transpose(Q)
Second Step
The new location of V (or V') which is now the X axis, needs to be rotated
around Z (now the axis of rotation), to the new location of W or W'
W' = W * transpose(Q)
As the Z axis does not rotate we only need the new location of the Y
axis in this step to complete this step.
Y' = W' Zrotate(90deg)
= Z x W'
The actual rotaton matrix in this axis framework is thus...
| W'x, W'y, W'z |
T = | Y'x, Y'y, Y'z |
| Zx, Zy, Zz | <- This is just (0, 0, 1)
Third Step
We just rotate back to the original coordinate system...
This was the original matrix Q calculated in step one.
The completed rotation matrix is thus..
Rotate_V_to_W = R = transpose(Q) * T * Q
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The following is vector stuff, not matrix...
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Distance of a point to a line.
Given line AB, Point C some distance away.
Minimim distance of C to line (perpendicular to line)
r = (AB . AC) / |AB|^2
WRONG: that is the distance of C from A in the direction of A to B!
That is length along the line!
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From http://www.cit.gu.edu.au/~anthony/info/graphics/matrix_vector.hints
Friday, March 27, 2009
Matrix Vector hints
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